Narwhal0411idn
Answered

Explore a diverse range of topics and get answers from knowledgeable individuals on IDNLearn.com. Find the information you need quickly and easily with our comprehensive and accurate Q&A platform.

80 POINTS! NO LINKS

How much ribbon would be needed to go around a package that had a length 2x^2+3x-5/x^2+x-3 centimeters and width x^2-x-5/x^2+x-3 centimeters?

80 POINTS NO LINKS How Much Ribbon Would Be Needed To Go Around A Package That Had A Length 2x23x5x2x3 Centimeters And Width X2x5x2x3 Centimeters class=

Sagot :

Raphealnwobiidn

The amount of ribbon needed to go around a package that had a length 2x² + 3x -5/(x² + x - 3) centimeters and width x² - x - 5 / (x² + x - 3) is

[tex]\frac{(2x^2+3x-5)(x^2-x-5)}{(x^2+x-3)^2}[/tex]

What is an equation?

An equation is an expression that shows the relationship between two or more number and variables.

The  length 2x² + 3x -5/(x² + x - 3) centimeters and width x² - x - 5 / (x² + x - 3) centimeters. Hence:

[tex]Area=\frac{2x^2+3x-5}{x^2+x-3} *\frac{x^2-x-5}{x^2+x-3} =\frac{(2x^2+3x-5)(x^2-x-5)}{(x^2+x-3)^2}[/tex]

The amount of ribbon needed to go around a package that had a length 2x² + 3x -5/(x² + x - 3) centimeters and width x² - x - 5 / (x² + x - 3) is

[tex]\frac{(2x^2+3x-5)(x^2-x-5)}{(x^2+x-3)^2}[/tex]

Find out more on equation at: https://brainly.com/question/2972832

#SPJ1

Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. For clear and precise answers, choose IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.