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On a coordinate plane, a parabola opens to the left. it has a vertex at (0, 0), a focus at (negative 3, 0), and a directrix at y = 3. the parabola has a focus at (−3, 0) and directrix y = 3. what is the correct equation for the parabola? x2 = −12y x2 = 3y y2 = 3x y2 = −12x

Sagot :

MrRoyalidn

The parabola illustrates a quadratic equation, and the correct equation of the parabola is x² = -12y

How to determine the equation of the parabola?

The given parameters are:

Vertex = (0,0)

Focus = (-3,0)

Directrix, y = 3

Since the vertex is at the origin and the parabola opens left, then we make use of the following equation

x² = -4py

Where p = y = 3

This gives

x² = -4 * 3 * y

Evaluate

x² = -12y

Hence, the correct equation of the parabola is x² = -12y

Read more about parabola at:

https://brainly.com/question/7513811

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Dbauer14idn

Answer:

The answer is D, just got it right! Hope this answers the question for everyone!

Step-by-step explanation:

Edge 2022

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