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Identify the center and the radius of the circle with equation (x+3)^2+(y-4)^2+16
Center: _____
Radius: _____

(answer choices)
(3,-4)
(-3,4)
16
4
256
(4,-3)

Sagot :

                                    Solution:

[tex](x+3)^2+(y-4)^2+16[/tex]

The center of the circle is at: [tex]C=(-3,4)[/tex]

The radius of the circle is [tex]r=4[/tex].

                                   explanation:

A circle with center at [tex](h,k)[/tex] and a radius of [tex]r[/tex] has equation [tex](x-h)[/tex]

In this example our circle equation can be written as:

[tex](x-(-3))^2+(y-4)^2=(4)^2[/tex]

So, we have: [tex]h=-3,k=4[/tex] and [tex]r=4[/tex]

Learn more about finding the center and the radius of a circle here:

brainly.com/question/11779639

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