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The sum of the first 8 terms of the geometric series ( 80, 20, 5, ... ) to the nearest integer is 1747600.
What is the Sum of the first 8 terms of the geometric sequence?
Using the formula;
Sn = a₁ * ( (1-rⁿ)/(1-r) )
Given that;
80,20,5,...
- nth term n = 8
- First value a₁ = 80
- Common ratio r = 4
We substitute our values into the expression above.
Sn = a₁ × ( (1-rⁿ)/(1-r) )
Sn = 80 × ( (1-4⁸)/(1-4) )
Sn = 80 × ( (1-65536)/(1-4) )
Sn = 80 × ( -65535 / -3 )
Sn = 80 × 21845
Sn = 1747600
Therefore, the sum of the first 8 terms of the geometric series ( 80, 20, 5, ... ) to the nearest integer is 1747600.
Learn more about geometric series here: https://brainly.com/question/19458543
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