Answered

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On a certain hot​ summer's day, 613 people used the public swimming pool. The daily prices are $1.75 for children and $2.00 for adults. The receipts for admission totaled $1170.75 How many children and how many adults swam at the public pool that​ day?

Sagot :

Answer:

1.59C + 2.25A = 786.75

C + A = 33    (even if all were the higher paying  adults, that would only be 33x2.25=74.25  far less than <<786.75)

1.59C + 1.59A = 33(1.59) = 52.47   subtract to eliminate C

     (2.25-1.59)A = 786.75 -52.47 = 734.28

       .66A = 734.28

            A = 73428/66 = 1112.55 = about 1113  adults

C = 33-1113 = -1080 children

which makes no sense.  over a thousand  "negative" children?  the public pool gave refunds to over a thousand prepaid children who didn't show up?  but a public swimming pool, no matter how large, probably wouldn't accomodate 1113 adults.

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