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[tex]\text{Let the missing numbers be x and y}\\\\~~~~~~~\dfrac 37 = \dfrac x{14} = \dfrac y{35}\\\\\\\implies \dfrac 37 = \dfrac x{14}\textbf{,}~~~\dfrac 37 = \dfrac y{35}\\ \\\\\implies x = \dfrac{3 \times 14}{7}\textbf{,}~~~ y =\dfrac{35 \times 3}{7} \\\\\\\implies x =6\textbf{,}~~~ y = 15\\\\\\\text{Hence,} ~ \dfrac 37 =\dfrac 6{14} = \dfrac {15}{35}[/tex]