Answer:
15
Step-by-step explanation:
Exponent law:
[tex]\boxed{\left(\dfrac{a}{b}\right)^{-m}=\left(\dfrac{b}{a}\right)^m}\\\\\boxed{\dfrac{a^m}{a^n}=a^{m-n}}\\\\\boxed{(a^{m})^n=a^{m*n}}[/tex]
[tex]\sf \left(\dfrac{5}{9}\right)^{-2}*\left(\dfrac{3}{5}\right)^{-3}*\left(\dfrac{3}{5}\right)^0=\left(\dfrac{5}{9}\right)^{-2}*\left(\dfrac{3}{5}\right)^{-3}*1\\\\ \text{Any variable or number raised to 0 =1} \\[/tex]
[tex]= \left(\dfrac{9}{5}\right)^2*\left(\dfrac{5}{3}\right)^3}\\\\= \dfrac{(3^2)^2}{5^2}*\dfrac{5^3}{3^3}\\\\=\dfrac{3^{2*2}}{5^2}}*\dfrac{5^3}{3^3}\\\\=\dfrac{3^{4}}{5^{2}}*\dfrac{5^3}{3^3}\\\\=3^{4-3}*5^{3-2}\\\\=3^1*5^{1}\\\\=15[/tex]
