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In ΔJKL, k = 430 cm, l = 590 cm and ∠J=117°. Find the length of j, to the nearest centimeter

Sagot :

Defnotmishidn

Answer:

j²=k²+l²-2klCosJ

j²=430²+590²-2(430)(590)Cos117

j=874cm

Step-by-step explanation:

Use the formula of triangles.

make sure to square root at the second last step where j²=763 354,7797

therefore your answer will be 874cm if you round off correctly to the nearest centimeter.

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