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In AABC, AB = 2 and AC = 11. Find m2C to the nearest degree.
help please​

In AABC AB 2 And AC 11 Find M2C To The Nearest Degreehelp Please class=

Sagot :

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Answer:

10

Step-by-step explanation:

Calculating BC

BC = √2^2 + 11^2

BC = √ 4+121

BC = √ 125 = 11.18

to find measure of angle C use sinerule

sinC/C = sinA/A

sinC/2= Sin90/11.18

SinC = 2×1/11.18

sinC = 2/11.18

sinC = (0.1788)

C = sin^-1(0.1788)

C = 10.305

C = 10 (approximately)

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