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The quadratic formula is:
[tex]\frac{-b + \sqrt{b^2 - 4ac} }{2a}[/tex] and [tex]\frac{-b - \sqrt{b^2 - 4ac} }{2a}[/tex]
In this case, a = 2, b = -3, and c = -7
So, we can plug in the numbers to get:
[tex]\frac{-(-3) + \sqrt{(-3)^2 - 4(2)(-7)} }{2(2)}[/tex] and [tex]\frac{-(-3) - \sqrt{(-3)^2 - 4(2)(-7)} }{2(2)}[/tex]
Simplifying, we get:
[tex]\frac{3 + \sqrt{65} }{4}[/tex] and [tex]\frac{3 - \sqrt{65} }{4}[/tex]
You need to use a calculator to find what these would be in decimal form. The answer, rounded to the nearest tenth, is: x = 2.8, x = -1.3