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Answer:
[tex](-8)^2\neq-64[/tex]
Step-by-step explanation:
Using the distributive property to expand, we have
[tex](-8x^2y^2)^2=(-8)^2(x^2)^2(y^2)^2.[/tex]
Squaring each term, we have
[tex](-8x^2y^2)^2=64x^4y^4.[/tex]
The mistake was that [tex]8^2=64,[/tex] not [tex]-64.[/tex] Using the fact that [tex]8^2=64,[/tex] the right answer would be
[tex]\boxed{64x^4y^4}[/tex].
Answer:
64 shouldnt be negative anymore
Step-by-step explanation:
(-8x^2y^2)^2 = -64x^4y^4
when exapnding the left side it would be...
(-8x^2y^2)^2
Apply exponent rule (-a)^n = a^n
→ (8x^2y^2)^2
→ (8^2)(x^2)^2
→ (8^2) = 64
→ 64(x^2)^2 = 64x^4
Hope this helps. Let me know if you have any questions !
Have a nice rest of you day :)