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P-7/12>3/10 how do you solve this?

Sagot :

[tex]p-\frac{7}{12}>\frac{3}{10}\ \ \ \ | add\ \frac{7}{12}\\\\ p>\frac{3}{10}+\frac{7}{12}\ \ \ | make\ common\ denominator\\\\ p>\frac{18}{60}+\frac{35}{60}\\\\ p>\frac{53}{60}[/tex]
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