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Sagot :
If would help me explain if I break this into two pieces:
First: add the whole numbers 7 + 2 = 9
Second: add the fractions: In this example, because both of the fractions has the same denominator (the bottom number), you can just add the top numbers (numerators) 9 + 11 to get 20/12. Then, you need to simplify 20/12. You do that by figuring out how many times 12 goes into 12 and how much is left over. In this case, 12 goes into 20 one time with 8 left over. So, 20/12 = 1 8/12.
Now you add both of those two pieces together:
9 + 1 8/12 = 10 8/12.
Now you need to take it one step further to simplify the 8/12 part of the answer. 8/12 can be simplified to 2/3 (divide the 8 by 4 to get 2 and divide the 12 by 4 to get 3), so your final answer is:
10 2/3.
First: add the whole numbers 7 + 2 = 9
Second: add the fractions: In this example, because both of the fractions has the same denominator (the bottom number), you can just add the top numbers (numerators) 9 + 11 to get 20/12. Then, you need to simplify 20/12. You do that by figuring out how many times 12 goes into 12 and how much is left over. In this case, 12 goes into 20 one time with 8 left over. So, 20/12 = 1 8/12.
Now you add both of those two pieces together:
9 + 1 8/12 = 10 8/12.
Now you need to take it one step further to simplify the 8/12 part of the answer. 8/12 can be simplified to 2/3 (divide the 8 by 4 to get 2 and divide the 12 by 4 to get 3), so your final answer is:
10 2/3.
[tex]7\frac{9}{12}+2\frac{11}{12}=(7+2)+(\frac{9}{12}+\frac{11}{12})=9+\frac{9+11}{12}=9+\frac{20}{12}\\\\=9+\frac{12+8}{12}=9+\frac{12}{12}+\frac{8}{12}=9+1+\frac{8}{12}=10+\frac{8:4}{12:4}\\\\=10+\frac{2}{3}=\boxed{10\frac{2}{3}}\neq2[/tex]
the mixed number is greater than 1, therefore the sum of two mixed numbers is not be equal 2, it's greater than 2.
if we have 2 mixed numbers greater than 0!
the mixed number is greater than 1, therefore the sum of two mixed numbers is not be equal 2, it's greater than 2.
if we have 2 mixed numbers greater than 0!
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