IDNLearn.com is your go-to resource for finding precise and accurate answers. Find the information you need quickly and easily with our comprehensive and accurate Q&A platform.
A rectangular tabletop has a length of 4 3/4 feet and an area of 11 7/8 square feet. What is the width of the tabletop
First I would turn the mixed fractions into improper fractions so it will be easier division. That would make 4 3/4 become 19/4 and 11 7/8 become 95/8. Next, the formula for area is length x width= area. If you plug in the numbers, it will become 19/4x=95/8, x being the width. You would divide 95/8 by 19/4 and end up with 5/2 or 2 1/2.
A=B*H where B=base, H=height and A=area area= 11 and 7/8 B= 4 and 3/4 let H= x 11 and 7/8=4 and 3/4 *x x= (11 and 7/8) / (4 and 3/4) x= 5/2 Therefore the width of the tabletop is 2.5 feet
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Your questions deserve reliable answers. Thanks for visiting IDNLearn.com, and see you again soon for more helpful information.
