IDNLearn.com connects you with a global community of knowledgeable individuals. Ask any question and receive timely, accurate responses from our dedicated community of experts.
Sagot :
We need 8.8 mL of acetic acid
Explanation:
Step 1: Data given
Mass of Copper oxide (CuO) = 0.035 grams
Molar mass CuO = 79.545 g/mol
Molarity acetic acid = 0.10 M
Step 2: The balanced equation
CuO + 2CH3COOH → Cu(CH3COO)2 + H2O
Step 3: Calculate moles CuO
Moles CuO = mass CuO / molar mass CuO
Moles CuO = 0.035 grams / 79.545 g/mol
Moles CuO = 4.4 *10^-4 moles
Step 4: Calculate moles CH3COOH
For 1 mol CuO we need 2 moles CH3COOH to produce 1 mol Cu(CH3COO)2 and 1 mol H2O
For 4.4 *10^-4 moles CuO we'll have 2 * 4.4 * 10^-4 = 8.8 *10^-4 moles
Step 5: Calculate volume of acetic acid
Volume acetic acid = moles acetic acid / molarity
Volume acetic acid = 8.8 * 10^-4 moles / 0.10 M
Volume acetic acid = 0.0088 L = 8.8 mL
We need 8.8 mL of acetic acid
Explanation:
Step 1: Data given
Mass of Copper oxide (CuO) = 0.035 grams
Molar mass CuO = 79.545 g/mol
Molarity acetic acid = 0.10 M
Step 2: The balanced equation
CuO + 2CH3COOH → Cu(CH3COO)2 + H2O
Step 3: Calculate moles CuO
Moles CuO = mass CuO / molar mass CuO
Moles CuO = 0.035 grams / 79.545 g/mol
Moles CuO = 4.4 *10^-4 moles
Step 4: Calculate moles CH3COOH
For 1 mol CuO we need 2 moles CH3COOH to produce 1 mol Cu(CH3COO)2 and 1 mol H2O
For 4.4 *10^-4 moles CuO we'll have 2 * 4.4 * 10^-4 = 8.8 *10^-4 moles
Step 5: Calculate volume of acetic acid
Volume acetic acid = moles acetic acid / molarity
Volume acetic acid = 8.8 * 10^-4 moles / 0.10 M
Volume acetic acid = 0.0088 L = 8.8 mL
We need 8.8 mL of acetic acid
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find clear and concise answers at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.
