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Sagot :
Two wires increase in length by the same amount when both their temperatures increase by the same amount, the shortness of the wire before the temperature increase is mathematically given as
dL=0.1485m
How much shorter is the shorter wire before the temperature increase?
Generally, the equation for change in length is mathematically given as
[tex]dl=lo \alpha dt[/tex]
Therefore
dl1=dl2
Where
a2=1.35a1
Hence
a1l1dt= a2l2dt
a1(1.2525)= a1*(1.135)(l2)
L2=1.104m
In conclusion, a change in length due to temperature is
dL=1.2525-1.104m
dL=0.1485m
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