LlMissincrediblellidn
Answered

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[tex]\sf\large\green{\underbrace{\red{Question*}}}:[/tex]

[tex] \mathcal \pink{Solve} [/tex]
[tex] \blue{3(x - 2) + 2(x + 1) = 10}[/tex]
​

Sagot :

Loneguyidn

[tex]~~~~~~~3(x-2) +2(x +1) = 10\\\\\implies 3x -6 + 2x+2 = 10\\\\\implies 5x -4 = 10\\\\\implies 5x = 10+4\\\\\implies 5x = 14 \\\\ \implies x = \dfrac{14}5 \\\\ \implies x = 2.8[/tex]

[tex]\large{\underline{\underline{\pmb{\sf{\color {red}{Solve:}}}}}}[/tex]

[tex] \sf \red{3(x - 2) + 2(x + 1) = 10}[/tex]

[tex]\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}[/tex]

In the above question, it is said to find out the value of "x". So, let's solve.

First we gonna multiply (x - 2) with 3 and then again (x + 1) with 2.

So, it goes...

[tex]3(x - 2) + 2(x + 1) = 10 \\ \\ \implies \: 3x - 6 + 2x + 2 = 10 \\ \\ \implies \: 5x - 4 = 10 \\ \\ \implies \: 5x = 10 + 4 \\ \\ \implies5x = 14 \\ \\ \implies \: x = \frac{14}{5} \\ \\ \implies \: x = 2.8[/tex]

Therefore, we've found the value of "x" and that is 2.8

[tex] \boxed{ \frak \pink{Have \: a \: Splendid \: Day}}[/tex]

[tex] \boxed{ \frak \green{Be \: Brainly}}[/tex]

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