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Question 8: The equation of motion of a particle is

s = t^3 4t^2 + 2t + 8
Where s is in meters
and t is in seconds

Find the acceleration after t=5 seconds.

Question 8 The Equation Of Motion Of A Particle Is S T3 4t2 2t 8 Where S Is In Meters And T Is In Seconds Find The Acceleration After T5 Seconds class=

Sagot :

Answer:

D) [tex]22\:\text{m/s}^2[/tex]

Step-by-step explanation:

Acceleration is the derivative of velocity, which is the derivative of position, so we must differentiate the function twice:

Position of Particle: [tex]s(t)=t^3-4t^2+2t+8[/tex]

Velocity of Particle: [tex]v(t)=3t^2-8t+2[/tex]

Acceleration of Particle: [tex]a(t)=6t-8[/tex]

After [tex]t=5[/tex] seconds, the acceleration of the particle is [tex]a(5)=6(5)-8=30-8=22\:\text{m/s}^2[/tex]

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