Answered

IDNLearn.com helps you find the answers you need quickly and efficiently. Get the information you need from our experts, who provide reliable and detailed answers to all your questions.

Sonji bought a combination lock that opens with a four-digit number created using the digits 0 through 9. The same digit cannot be used more than once in the combination.

If Sonji wants the last digit to be a 7 and the order of the digits matters, how many ways can the remaining digits be chosen?

Sagot :

Answer:

504 ways

Step-by-step explanation:

We know that since Sonji wants the last digit to be 7 and that numbers don't repeat, there are only 9 possibilities for the first digit, 8 possibilities for the second digit, 7 possibilities for the third digit, and 1 possibility for the fourth digit (which is 7).

Using the Fundamental Counting Principle, there are 9*8*7*1 = 504 ways for the remaining digits to be chosen.

Sakshamisntgayidn

Answer:

B. 504

Step-by-step explanation:

Have a good day!

Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. IDNLearn.com provides the answers you need. Thank you for visiting, and see you next time for more valuable insights.