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The approximate difference in their volumes is 17.2 cubic inches
The given parameters are:
Diameter, d = 2.8
Diameter, D = 3.8
The radii are the half of the diameter.
So, we have:
r = 1.4
R = 1.9
The volume of the balls is then calculated using:
[tex]V = \frac{4}{3}\pi r^3[/tex]
The difference is then represented as:
[tex]D = \frac{4}{3}\pi (R^3 - r^3)[/tex]
Substitute known values
[tex]D = \frac{4}{3}* 3.14* (1.9^3 - 1.4^3)[/tex]
Evaluate
D = 17.2
Hence, the approximate difference in their volumes is 17.2 cubic inches
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