Answered

Find the best solutions to your problems with the help of IDNLearn.com. Our experts are available to provide accurate, comprehensive answers to help you make informed decisions about any topic or issue you encounter.

- A straight wire, 0.20 m long, moves at a constant speed of 7.0 m/s
perpendicular to a magnetic field of strength 8.0×10-2 T.

A. What EMF is induced in the wire?
B. What is the direction of the induced current?
C. Determine the polarity of point A and point L
D. The wire is part of a circuit that has a resistance of 0.50 Ω. What is the
current through the wire?

A Straight Wire 020 M Long Moves At A Constant Speed Of 70 Ms Perpendicular To A Magnetic Field Of Strength 80102 T A What EMF Is Induced In The Wire B What Is class=

Sagot :

Onyebuchinnajiidn

(a) The emf induced in the wire is 0.112 V.

(b) The direction of the current will into the page.

(c) The polarity of A will be positive and L will be negative.

(d)  The current flowing through the wire is 0.224 A.

EMF induced in the wire

The emf induced in the wire is calculated as follows;

EMF = BLv

EMF = (8 x 10⁻²) x 0.2 x 7

EMF = 0.112 V

Direction of the current

Since, the magnetic field is out of the page, the current will follow counter clockwise and will point into the page.

Polarity of point A and point L

The current is flowing counter currently, hence the polarity of A will be positive and L will be negative.

Current through the wire

V = IR

I = V/R

I = (0.112)/0.5

I = 0.224 A

Learn more about current here: https://brainly.com/question/24858512

#SPJ1

We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com is your go-to source for accurate answers. Thanks for stopping by, and come back for more helpful information.