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12.36:
the measures of two angles in a parallelogram add to [tex]204^{\circ}[/tex] . find the measure of each of the other two angles.


Sagot :

Step-by-step explanation:

in a parallelogram we have 2 equally large angles and 2 equally small angles.

the sum of all 4 angles must be 360°.

so let's first determine what angles are together 204°.

if it would be 2 neighboring angles, it would be the sum of a large and a small angle.

and the sum of the remaining 2 angles would be the same (again 204°).

but that that would together be 408°. too much.

so, it can only be that the 2 given angles are a pair of equal angles. and each would be

204/2 = 102°

as they are larger than 90°, they are the large angles in the parallelogram.

so, the other 2 angles are the pair of equally large small angles. together they have

360 - 204 = 156°

and each one is then

156/2 = 78°

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