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In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect and . Then, intersecting arcs of equal size are drawn centered at points D and E. Point P is located at the intersection of these arcs.

Based on this construction, m∠ABP is
°, and m∠ABC is
°.

In The Diagram Points D And E Are Marked By Drawing Arcs Of Equal Size Centered At B Such That The Arcs Intersect And Then Intersecting Arcs Of Equal Size Are D class=

Sagot :

Batolisisidn

The measure of ∠ABP and ∠ABC are 32° and 64° respectively.

what is a bisector of an angle?

Any line which divides an angle into two equal halves is a bisector of that angle.

Analysis:

Since the arcs at D and E are drawn with the same radius and arc using center D and E are intersected by line PB( which is the bisector of the full arc with center B) then ∠ABP = ∠PBC = 32°.

∠ABC = ∠ABP + ∠PBC

∠ABC = 32 + 32 = 64°

In conclusion, ∠ABP and ∠ABC are 32° and 64°

Learn more about bisectors of angles: brainly.com/question/24334771

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