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20. calculate the molar enthalpy of vaporization of a substance, given that 0.433 mol of the substance absorbs 36.5 kj of energy when it is vaporized.

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The molar enthalpy of vaporization of the substance is 84.3 kj/mol.

What is molar enthalpy of vaporization?

Molar enthalpy of vaporization is the energy required to vaporize one mole of a liquid at its boiling point.

0.433 moles of the substance absorbs 36.5 kj of energy when it is vaporized.

1 mole of the substance will absorb 36.5 kJ × 1 /0.433mol = 84.3 kj/mol

Therefore, the molar enthalpy of vaporization of the substance is 84.3 kj/mol.

Learn more about molar enthalpy of vaporization at: https://brainly.com/question/22971824

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