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PLS HELP ASAP find the measure of side b. round to the nearest whole number

PLS HELP ASAP Find The Measure Of Side B Round To The Nearest Whole Number class=

Sagot :

Answer:

b=204

Step-by-step explanation:

The law of sine states that: [tex]\frac{SinA}{a} =\frac{SinB}{b} =\frac{SinC}{c}[/tex]

We know that a triangle has 180° total, so we can subtract the two angle measures we know to find the third angle: [tex]180-90-41=49[/tex]°.

Using these two things, we can come up with the equality [tex]\frac{Sin90^{o} }{270} =\frac{Sin49^o}{b}[/tex], which we can use to solve for side b.

[tex]\frac{Sin90^o}{270} =\frac{1}{270}[/tex], so we know that [tex]\frac{1}{270} =\frac{Sin49^o}{b}[/tex].

Next, we would multiply both sides by b to get [tex]\frac{1}{270}b=Sin49^o[/tex].

Sin49°≈0.75471, so to find b we would multiply 0.75471×270=203.77

Since the problem asks us to round to the nearest whole number, b=204

Hope this helps! :)