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For what value of the constant a will the system of linear equations 6x-5y=3 and 3x+ay=1 have no solution

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The value of the constant a will the system of linear equations 6x-5y=3 and 3x+ay=1 have no solution is -5/2

System of equation

For a system of equation to have no solution, the expression on both sides must be different.

Given the system of equation

6x-5y=3 and

3x+ay=1

For the equations to have no solution, the a1/a2= b1/b2

Substitute

6/3 = -5/a


Cross multiply

2 = -5/a

a= -5/2

Hence the value of the constant a will the system of linear equations 6x-5y=3 and 3x+ay=1 have no solution is -5/2

Learn more on system of equation here: https://brainly.com/question/14323743

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