Answered

Discover a wealth of information and get your questions answered on IDNLearn.com. Ask anything and receive thorough, reliable answers from our community of experienced professionals.

a house and lot cost $120,000. if the house cost 3 times more than the lot, how much did the house cost?

Sagot :

XxxAceOfSpadesxxxidn

Answer:

$90,000

Step-by-step explanation:

We can can use substitution for this. First, we need to create two separate problems that represent this situation. The house and the lot together cost 120000, so we can make the equation h+l=120000. We also know that the house is worth 3 lots, so we can make the equation h=3l. Because h=3l, we can substitute for h, making the equation 3l+l=120000, or 4l=120000. To isolate l, we have to divide both sides by 4. If we do that, we get l=30000. Now, we have to substitute to find h. Our new equation is h+30000=120000. To isolate h, we have to subtract 30000 from each side. If we do this, we get h=90000. That's our answer.

Hope this helps!

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.