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Sagot :
Answer:
The airplane flies 95 miles.
Step-by-step explanation:
- First we need to find the distance for the first segment using the formula for distance [tex]D=\sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}[/tex]. Let's say [tex](x_{1},y_{1})[/tex] is (0, 0) and [tex](x_{2},y_{2})[/tex] is (33, 56). This gets us that the length of this segment is 65 miles.
- Next, we need to find the distance for the second segment. Using the same formula for distance [tex]D=\sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}[/tex], we can say [tex](x_{1},y_{1})[/tex] is now (33, 56) and [tex](x_{2},y_{2})[/tex] is now (23, 32). This gets us that the length of this segment is 26 miles.
- To get the total distance traveled, add the length of these two segments together (65 miles + 26 miles) to get 91 total miles traveled.
Question:
An airplane flies from City 1 at (0, 0) to City 2 at (33, 56) and then to City 3 at (23, 32). What is the total number of miles it flies? Each unit represents 1 mile.
Answer:
The plane flew 91 miles.
Step-by-step explanation:
City 1 - City 2
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[tex]d_{1}[/tex] = [tex]\sqrt{(33 - 0)^{2} + (56 - 0)^{2}[/tex]
[tex]d_{1}[/tex] = [tex]\sqrt{33^{2} + 56^{2}[/tex]
[tex]d_{1[/tex] = [tex]\sqrt{1089 + 3136[/tex]
[tex]d_{1}[/tex] = [tex]\sqrt{4225}[/tex]
[tex]d_1[/tex] = [tex]65[/tex]
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City 2 - City 3
[tex]d_2[/tex] = [tex]\sqrt{(33 - 23)^2 + (56 - 32)^2[/tex]
[tex]d_2[/tex] = [tex]\sqrt {10^2 + 24^2}[/tex]
[tex]d_2[/tex] = [tex]\sqrt{676}[/tex]
[tex]d_2[/tex] = 26
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[tex]d_1 + d_2 = 65 + 26[/tex]
[tex]d_1 + d_2 = 91[/tex]
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Therefore, the airplane flew a total of 91 miles through every city
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<3 Lots of love!
-The Book Worm.
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