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Predict the products and write the balanced Equation for the following:
“Aqueous Copper (II)Chloride reacts with aqueous Tin (IV) Nitrite."


Sagot :

Answer:

2 CuCl₂ (aq) + Sn(NO₂)₄ (aq) ---> 2 Cu(NO₂)₂ (aq) + SnCl₄ (aq)

Explanation:

You can safely assume that this is a double-displacement reaction. In these reactions, the cation of one molecule is substituted for the cation of another molecule, and vice versa. Once the reaction occurs, you are left with the products:

copper (II) chloride + tin (IV) nitrite ---> copper (II) nitrite + tin (IV) chloride

The balanced equation is:

2 CuCl₂ (aq) + Sn(NO₂)₄ (aq) ---> 2 Cu(NO₂)₂ (aq) + SnCl₄ (aq)