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A block with mass m = 2 kg slides down from a friction less ramp (mu = 0). If the angle theta is 25 degrees, find the acceleration of the block.

A Block With Mass M 2 Kg Slides Down From A Friction Less Ramp Mu 0 If The Angle Theta Is 25 Degrees Find The Acceleration Of The Block class=

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Lanuelidn

Based on the calculations, the acceleration of this block as it slides down from the friction less ramp is equal to 0.85 m/s².

How to determine the acceleration of the block?

In order to determine the acceleration of this block, we would apply Newton's Second Law of Motion while taking moment about the tensional force.

The vertical component of the tensional force that is acting on the block as it slides down from this friction less ramp is given by:

T = Ma - Mgsinθ

0 = Ma - Mgsinθ

Ma = Mgsinθ

a = gsinθ

Substituting the given parameters into the formula, we have;

a = 9.8 × sin25

a = 9.8 × 0.4226

Acceleration, a = 0.85 m/s².

Read more on acceleration here: https://brainly.com/question/25961211

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