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The domain is [tex]x \le 5[/tex] and the range of the function is [tex]f(x) \ge - 3[/tex]
The function is given as:
[tex]f(x) = \sqrt{5 - x} - 3[/tex]
The radicand must be at least 0.
So, we have:
[tex]\sqrt{5 - x} \ge 0[/tex]
Square both sides
[tex]5 - x \ge 0[/tex]
Rewrite as:
[tex]5 \ge x[/tex]
Solve for x
[tex]x \le 5[/tex]
This means that the domain is [tex]x \le 5[/tex]
For the range, we have; [tex]\sqrt{5 - x} \ge 0[/tex]
This means that:
[tex]f(x) \ge 0 - 3[/tex]
[tex]f(x) \ge - 3[/tex]
Hence, the range of the function is [tex]f(x) \ge - 3[/tex]
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