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Answered

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What is the center of the circle described by the equation (x-6)² + (y + 5)² = 25?
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Sagot :

Answer:   (6, -5)

Reason:

Rewrite the given equation into [tex](x-6)^2 + (y-(-5))^2 = 5^2[/tex]

I changed the y+5 into y-(-5), and also replaced 25 with [tex]5^2[/tex]

Then compare that to the circle template of [tex](x-h)^2 + (y-k)^2 = r^2[/tex]

We see that h = 6 and k = -5 to give a center of (h,k) = (6, -5)

Side note: the radius is r = 5 units

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