Answered

IDNLearn.com is designed to help you find the answers you need quickly and easily. Discover the information you need from our experienced professionals who provide accurate and reliable answers to all your questions.

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

The shaded region in the graph represents the solutions of this system of linear inequalities:

y ___

4x + ___

y ≤ ___

x + ___


Note: Use the symbols <, >, <=, and >= for inequality signs.

Type The Correct Answer In Each Box Use Numerals Instead Of Words If Necessary Use For The Fraction Bars The Shaded Region In The Graph Represents The Solutions class=

Sagot :

Lanuelidn

Based on the calculations, the solutions of this system of linear inequalities are equal to:

  1. y < 4x + 5
  2. y ≤ 2x + 3

What is an inequality?

An inequality simply refers to a mathematical relation that's used to compare two (2) or more integers (variables) in an equation based on any of the following:

  • Greater than (>).
  • Less than (<).
  • Greater than or equal to (≥).
  • Less than or equal to (≤).

In order to determine the solutions of this system of linear inequalities, we would find the slope of each line.

For line A, we have:

Slope, m = (11 - 3)/(4 - 0) = 8/4

Slope, m = 2.

Mathematically, the standard equation of a line is given by y = mx + b.

y = 2x + 3

y ≤ 2x + 3.

For line B, the slope is equal to 4. Also, the y-intercept from the graph is equal to 5.

Therefore, the standard equation of a line is given by:

y = 4x + 5

y < 4x + 5

In conclusion, the solutions of this system of linear inequalities are equal to:

  1. y < 4x + 5
  2. y ≤ 2x + 3

Read more on linear inequalities here: https://brainly.com/question/21103162

#SPJ1

We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is your go-to source for dependable answers. Thank you for visiting, and we hope to assist you again.