Answered

IDNLearn.com: Your reliable source for finding expert answers. Join our knowledgeable community and get detailed, reliable answers to all your questions.

what mass in grams of hydrogen is produced by the reaction of 4.73 g of magnesium with 1.83 of water

Sagot :

Oseniidn

The mass, in grams, of hydrogen that would be produced from the reaction will be 0.102 grams

Stoichiometric calculations

From the balanced equation of the reaction:

[tex]Mg + 2H_2O -- > Mg(OH)_2 + H_2[/tex]

The mole ration of magnesium to water is 1:2.

Mole of 4.73 grams Mg = 4.73/24.3 = 0.195 moles

Mole of 1.83 grams water = 1.83/18 = 0.102 moles

Hence, water is limiting.

Mole ratio of water to the hydrogen produced = 2:1

Equivalent mole of hydrogen gas produced = 0.102/2 = 0.05 moles

Mass of 0.05 moles hydrogen gas = 0.05 x 2 = 0.102 grams

More on stoichiometric calculations can be found here: https://brainly.com/question/27287858

#SPJ1

Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.