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A hyperbola centered at the origin has a vertex at (0,−40) and a focus at (0, 41). which are the equations of the asymptotes? y = ±x y = ±x y = ±x y = ±x

Sagot :

The equations of the asymptotes of the given hyperbola are; y = ±(40/9)x

How to Interpret the equation of a hyperbola?

We are given;

Vertex at (0,−40)

Focus at (0, 41).

Thus, the equation of the asymptote of the given hyperbola is;

y = ±(40/(√41 - (-40))

y = ±(40/(√81)

y = ±40/9

Read more about Hyperbola Equation at; https://brainly.com/question/13003184

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