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A survey of pet owners found that on average, they spend $1,225 annually per pet, with a standard deviation of $275. between which two amounts would you expect 95% of the survey’s respondents to spend annually per pet if the sample is approximately normal and comes from a normally distributed population?

Sagot :

Parrainidn

Based on the sample being normal, 95% of the survey's respondents will fall within $675 and $1,775.

Where will 95% of the respondents fall?

A 95% interval has a z value of 1.96.

The confidence interval would be:

= Sample mean ± z x (Standard deviation / √sample)

= 1,225 + 1.96 x (275 / √1)

= $1,764

= 1,225 - 1.96 x (275 / √1)

= $686

The closest figures from the options are $675 and $1,775.

Options for this question include:

  • $675 and $1,500
  • $675 and $1,775
  • $950 and $1,500
  • $950 and $1,775

Find out more on 95% confidence intervals at https://brainly.com/question/16974109.

#SPJ1

Answer:

option 3

Explanation:

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