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A ball is thrown upward in the air. The height h, in feet, of the ball t seconds
after being thrown can be determined by the equation
h=-16t² + 40t + 4
How long does it take for the ball to hit the ground? Round to one decimal
place.

A Ball Is Thrown Upward In The Air The Height H In Feet Of The Ball T Seconds After Being Thrown Can Be Determined By The Equation H16t 40t 4 How Long Does It T class=

Sagot :

Facundo3141592idn

By solving a quadratic equation, we will see that the ball hits the ground after 2.6 seconds.

How long does it take for the ball to hit the ground?

Here we need to solve the equation:

h(t) = 0 = -16t² + 40t + 4

This represents that the ball hits the ground.

So we just need to solve that quadratic equation, using the general formula we get:

[tex]t = \frac{-40 \pm \sqrt{(40)^2 - 4*4*(-16)} }{2*-16} \\\\t = \frac{-40 \pm 43.1 }{-32}[/tex]

We only care for the positive solution, which is:

t = (-40 - 43.1)/-32 = 2.6s

So the ball hits the ground after 2.6 seconds.

If you want to learn more about quadratic equations:

https://brainly.com/question/1214333

#SPJ1

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