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A fighter tank targets an enemy helicopter flying at an altitude of 1250 ft. If the ground
distance between the tank & the helicopter is 875 ft, what angle of elevation must the
cannon be raised to in order to hit the target?

Sagot :

Facundo3141592idn

By using trigonometric relations, we will see that the angle of elevation must be 55°.

How to find the angle of elevation?

We can see this as a right triangle, where one cathetus measures 1250ft (altitude) and the other cathetus measures 875ft.

The angle of elevation is the angle such that the adjacent cathetus is the one measuring 875ft.

Then we can use the relation:

tan(a) = (opposite cathetus)/(adjacent cathetus)

tan(a) = 1250ft/875ft

To find the angle of elevation, we can use the inverse tangent function:

a = Atan(1250ft/875ft) = 55°

The angle of elevation must be 55 degrees.

If you want to learn more about right triangles:

https://brainly.com/question/2217700

#SPJ1

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