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The time it would take for the bacteria to reach 1119 is 5.83 hours
Given the function:
[tex]Pt= P_0e^k^t[/tex]
To find the exponential growth;
80 = [tex]50e^k^*^3[/tex]
[tex]k= 1.6/3\\k= 0.533[/tex]
If there is a constant growth, then to get to 1119:
1119= [tex]50e^0^.^5^3^3^*t[/tex]
3.8 = 0.533*t
t= 5.83 hours
Therefore, it would take 5.83 hours for the bacteria to increase to 1119.
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