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Identify the zeros given the quadratic equation y= -16(x+7)(x-5)

Sagot :

Peachyyythymeidn

Answer:

wouldn't it be -7 and 5? I'm pretty sure that you switch the signs around.

Step-by-step explanation:

set y=0 and solve. -7 + 7 = 0 and 5 - 5 = 0. my teacher told me to switch the signs for each factored term. hope this helps.

Chetankachanaidn

Answer:

x = -7

x = 5

Step-by-step explanation:

Hello!

We can use the Zero Product Property to solve for the Zeroes.

Zero product Property

The zero product property stars by factoring a quadratic. You then set each of the factors to zero, and solve for the variable in the factor.

Factored form: y = a(x - h)(x - k)

  • 0 = a(x - h)(x - k)
  • 0 = (x - h)(x - k)        Divide by a

Now, let's call each factor, A and B. To get to 0, either A, B, or both have to be 0. We prefer to solve for both.

Solve

  • y = -16(x + 7)(x - 5)
  • 0 = -16(x + 7)(x - 5)
  • 0 = (x + 7)(x - 5)   Divide by -16
  1. x + 7 = 0, x = -7
  2. x - 5 = 0, x = 5

The zeroes of the Quadratic is -7 and 5.

Why do we replace it with 0?

Zeroes means the x-intercepts, or the roots of a quadratic. An x-intercet is when y is equal to 0. So we replace y with 0, and solve for x.

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