Answered

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what is the slope-intercept form of the equation of the line with the following points? (-3,5), (6,3)

Sagot :

Answer:

Y=-0.22X+6.33

Step-by-step explanation:

Y-yo=m(X-x0)

punto A=(-3,5)

punto B=(6,3)

ecuacion de la recta: Y-yo=m(X-x0)

m=Pendiente=[tex]\frac{5-3}{(-3-6)} =\frac{2}{-9}[/tex]

sea B(6,3)  xo=6  y yo=3

reemplazando:

Y-6=[tex]\frac{-2}{9}[/tex](X-3)

Y-6=-0.22X+0.33

Y=-0.22X+6.33

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