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If set A contains four distinct numbers and set B contains seven distinct letters, how many elements are in (A U B)?​

Sagot :

MrRoyalidn

There are 11 elements are in (A U B)

How to determine the number of elements?

The given parameters are:

n(A) = 4

n(B) = 7

The number of elements in (A U B) is calculated using:

n(A U B) = n(A) +n(B) - n(A U B)

Given that the sets have distincts elements, we have:

n(A U B) = 4 + 7 - 0

Evaluate

n(A U B) = 11

Hence, there are 11 elements are in (A U B)

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