Answered

IDNLearn.com: Where your questions meet expert advice and community insights. Find accurate and detailed answers to your questions from our experienced and dedicated community members.


A softball pitcher throws a 0.17 kg ball toward a batter who is 20 m away. The
ball is traveling at 22 m/s when it leaves the pitcher's hand. What is the ball's
kinetic energy at this point?
OA. 4 J
OB. 82 J
C. 41 J

Sagot :

Answer:

C

Explanation:

Kinetic Energy formula :

K.E. = 1/2mv²

=============================================================

Given :

⇒ mass = 0.17 kg (needed)

⇒ distance = 20 m (not needed)

⇒ velocity = 22 m/s (needed)

============================================================

Solving :

⇒ K.E. = 1/2 × 0.17 × (22)²

⇒ K.E. = 11 × 0.17 × 22

⇒ K.E. = 1.87 × 22

⇒ K.E. = 41.14 ≈ 41 J
c fss trust good luck !!
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.