Answered

IDNLearn.com is designed to help you find the answers you need quickly and easily. Our experts provide prompt and accurate answers to help you make informed decisions on any topic.

Select the correct answer from each drop-down menu. a reaction proceeds with 2.72 moles of magnesium chlorate and 3.14 moles of sodium hydroxide. this is the equation of the reaction: mg(clo3)2 2naoh → mg(oh)2 2naclo3. determine the theoretical amount of each product that the reaction will produce. the reaction will produce of magnesium hydroxide and of sodium chlorate.

Sagot :

Oseniidn

334.22 grams of sodium chlorate and 91.56 grams of magnesium hydroxide would be produced respectively.

Stoichiometric calculation

From the equation of the reaction:

[tex]Mg(ClO_3)_2 + 2NaOH --- > 2NaClO_3 + Mg(OH)_2[/tex]

The mole ratio of magnesium chlorate to sodium hydroxide is 1:2.

With 2.72 moles of magnesium chlorate and 3.14 moles of sodium hydroxide provided respectively, the sodium hydroxide is limiting in availability.

Mole ratio of NaOH and [tex]NaClO_3[/tex] = 1:1

equivalent mole of  [tex]NaClO_3[/tex] = 3.14 moles

Mass of 3.14 moles  [tex]NaClO_3[/tex]  = 3.14 x 106.44 = 334.22 grams

Mole ratio of NaOH and [tex]Mg(OH)_2[/tex] = 2:1

Equivalent mole of  [tex]Mg(OH)_2[/tex] = 3.14/2 = 1.57 moles

Mass of 1.57 moles  [tex]Mg(OH)_2[/tex] = 1.57 x 58.32 = 91.56 grams

More on stoichiometric calculations can be found here: https://brainly.com/question/27287858

#SPJ1

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.