From personal advice to professional guidance, IDNLearn.com has the answers you seek. Join our Q&A platform to get accurate and thorough answers to all your pressing questions.
Sagot :
The increase in velocity of the student per second is 10 m/s^2 and her change in momentum each second is 500 kgm/s^2.
What is the change in velocity per second for any object falling freely under gravity?
The change in velocity of a moving object is known as acceleration.
For any object falling freely under gravity, the change in velocity per second or acceleration due to gravity is a constant and is equal to 10 metres per square second (10 m/s^2).
The change in momentum of a body is given as follows:
- Momentum = mass × velocity
- Change in momentum = mv - mu
- Change in momentum = m(v - u)
- acceleration = v - u
where m is mass, v is final velocity and u is final velocity.
Mass of the student = 50 Kg
Change in momentum each second = 50 kg × 10 m/s^2 = 500 kgm/s^2
Therefore, the increase in velocity of the student per second is 10 m/s^2 and her change in momentum each second is 500 kgm/s^2.
Learn more about change in momentum at: https://brainly.com/question/27778439
#SPJ1
Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.