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Sagot :
The quadratic equation that has a root of 6 and 2 is x^2 - 8x + 12 = 0
How to determine the quadratic equation?
The roots are given as:
x = 6 and x = 2
Rewrite as:
x - 6 = 0 and x - 2 = 0
Multiply both equations
(x - 6)(x - 2) = 0 * 0
Evaluate the product
x^2 - 6x - 2x + 12 = 0
Evaluate the difference
x^2 - 8x + 12 = 0
Hence, the equation that has a root of 6 and 2 is x^2 - 8x + 12 = 0
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