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Sagot :
The equation represents a line that passes through(4, 1/3) and has a slope of 3/4 option A; y - 1/3 = 3/4 ( x - 4).
What is the Point-slope form?
The equation of the straight line has its slope and given point.
If we have a non-vertical line that passes through any point(x1, y1) has gradient m. then general point (x, y) must satisfy the equation
y-y₁ = m(x-x₁)
Which is the required equation of a line in a point-slope form.
we know that
The equation of the line into point-slope form is equal to
y-y₁ = m(x-x₁)
we have
(x₁, y₁) = (4, 1/3)
m = 3/4
substitute the given values
y-y₁ = m(x-x₁)
y - 1/3 = 3/4 ( x - 4)
therefore,
y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)
Thus, option A is correct.
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