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If 33.9 ml of h3po4 neutralizes 23.4 ml of 2.28 m koh, what is the molarity of the phosphoric acid?

Sagot :

Medunno13idn

Answer: 1.57 M

Explanation:

[tex]M_{A}V_{A}=M_{B}V_{B}\\(33.9)M_{A}-=(23.4)(2.28)\\M_{A}=\frac{(23.4)(2.28)}{33.9}=\boxed{1.57 \text{ M}}[/tex]

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