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It took 55 days for a radioactivity of 1.75 x 1012 Bq to remain 0.135 Ci. What is the half-life of this radioactivity?

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From the calculations, we can see that the half life of the material is 11.4 days

What is radioactivity?

The term radioactivity refers to the spontaneous disintegration of a radioactive nucleus. The time taken for half of the radioactive material to remain.

Given that;

N/No = (1/2)^t/t1/2

N = amount that remained

No = amount that remained in the beginning

t = time taken

t1/2 = half life of the substance

N =Noe^-kt

4.995 ×10^9 = 1.75 x 10^12e^-55k

3.5* 10-2=e^-55k

k = ln3.5* 10-2/-55

k =0.06095

t1/2 = 0.693/0.06095

t1/2 = 11.4 days

Learn more about half life:https://brainly.com/question/24710827

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