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A supermarket customer has paid a total of 156 l for 24 L of milk, 6 kg of Serrano ham and 12 L of olive oil. Calculate the price of each item, knowing that a liter of oil costs three times more than a liter of milk and that a kilogram of ham costs the same as buying 4 L of oil plus 4 L of milk.

Sagot :

Let x, y, z denote the costs of milk, Serrano ham, and olive oil, respectively. Form the related system of equations and solve.

[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left\{\begin{matrix} 24x+6y+12z =156 \\ \ \qquad \qquad \quad \ z=3x \\ \qquad\ 4x+4z=y \end{matrix}\right.\ \Longrightarrow\ y=16x } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{ 156=24x+6(16x)+12(3x)=156x\Longrightarrow x=1 } \end{gathered}$}[/tex]

         [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{ y= 16\qquad z=3 } \end{gathered}$}[/tex]

Milk costs 1 a liter, Serrano ham 16 a kilogram and olive oil 3 a liter.

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